| /*** | |
| Md. Nazmul Hasan | |
| Shahjalal University of Science & Technology,Sylhet. | |
| hasan08sust@gmail.com | |
| ***/ | |
| #include<iostream> | |
| #include<cstdio> | |
| #include<stack> | |
| #include<queue> | |
| #include<map> | |
| #include<vector> | |
| #include<algorithm> | |
| #include<cstring> | |
| #include<sstream> | |
| #include<cmath> | |
| #include <iomanip> | |
| using namespace std ; | |
| typedef long long ll ; | |
| typedef int in ; | |
| typedef unsigned long long ull ; | |
| const double pi = 2*acos(0) ; | |
| #define maxi 40000 | |
| #define pf printf | |
| #define sc scanf | |
| #define pb push_back | |
| #define MEM(x,y) (memset((x),(y),sizeof(x))) | |
| #define MIN(x,y) ((x) < (y) ? (x) : (y)) | |
| #define MAX(x,y) ((x) > (y) ? (x) : (y)) | |
| #define load(array,size) for(int i=0 ; i<size ; i++) cin>>array[i] ; | |
| #define new_line pf("\n") | |
| #define clear_data(array) memset(array,0,sizeof(array)) | |
| #define highest_int 2147483647 | |
| int GCD(int a, int b) | |
| { | |
| if(a%b==0) return b; | |
| return GCD(b,a%b); | |
| } | |
| int main() | |
| { | |
| int test,p,mx,a,b,val; | |
| string str; | |
| vector<int>data; | |
| sc("%d",&test); | |
| getchar(); | |
| while(test--) | |
| { | |
| getline(cin,str); | |
| stringstream ss(str); | |
| while(ss>>p) | |
| { | |
| data.pb(p); | |
| } | |
| mx =0 ; | |
| for(int i=0 ; i<data.size()-1 ; i++) | |
| { | |
| for(int j=i+1 ; j<data.size() ; j++) | |
| { | |
| a = data[i]; | |
| b = data[j]; | |
| val = GCD(a,b); | |
| //pf("GCD OF %d & %d is %d\n",a,b,val); | |
| if(mx<val) | |
| { | |
| mx = val; | |
| } | |
| } | |
| } | |
| pf("%d\n",mx); | |
| data.clear(); | |
| } | |
| return 0; | |
| } |
12 November 2017
UVA 11827 - Maximum GCD
UVA 412 Pi
| /*** | |
| Md. Nazmul Hasan | |
| Shahjalal University of Science & Technology,Sylhet. | |
| hasan08sust@gmail.com | |
| ***/ | |
| #include<iostream> | |
| #include<cstdio> | |
| #include<stack> | |
| #include<queue> | |
| #include<map> | |
| #include<vector> | |
| #include<algorithm> | |
| #include<cstring> | |
| #include<sstream> | |
| #include<cmath> | |
| #include <iomanip> | |
| using namespace std ; | |
| typedef long long ll ; | |
| typedef int in ; | |
| typedef unsigned long long ull ; | |
| const double pi = 2*acos(0) ; | |
| #define maxi 40000 | |
| #define pf printf | |
| #define sc scanf | |
| #define pb push_back | |
| #define MEM(x,y) (memset((x),(y),sizeof(x))) | |
| #define MIN(x,y) ((x) < (y) ? (x) : (y)) | |
| #define MAX(x,y) ((x) > (y) ? (x) : (y)) | |
| #define load(array,size) for(int i=0 ; i<size ; i++) cin>>array[i] ; | |
| #define new_line pf("\n") | |
| #define clear_data(array) memset(array,0,sizeof(array)) | |
| #define highest_int 2147483647 | |
| int GCD(int a, int b) | |
| { | |
| if(a%b==0) return b; | |
| return GCD(b,a%b); | |
| } | |
| int main() | |
| { | |
| int n,m,p,cnt,a,b,d; | |
| vector<int>data; | |
| while(sc("%d",&n)) | |
| { | |
| if(n<=1 || n>=50) | |
| break; | |
| m = n-1; | |
| cnt =0 ; | |
| int total = m*(m+1)/2; | |
| for(int i=0 ; i<n ; i++) | |
| { | |
| sc("%d",&p); | |
| data.pb(p); | |
| } | |
| for(int i=0 ; i<data.size()-1 ; i++) | |
| { | |
| //j = i+1; | |
| for(int j = i+1 ; j<data.size() ; j++) | |
| { | |
| a = data[i]; | |
| b = data[j]; | |
| d = GCD(a,b); | |
| if(d==1) | |
| { | |
| cnt++; | |
| //pf("-> %d %d\n",a,b); | |
| } | |
| } | |
| } | |
| if(cnt==0) | |
| { | |
| pf("No estimate for this data set.\n"); | |
| } | |
| else | |
| { | |
| double val = (6*total*1.0)/cnt ; | |
| double pi = sqrt(val); | |
| pf("%.6lf\n",pi); | |
| } | |
| data.clear(); | |
| } | |
| return 0; | |
| } |
09 November 2017
UVA 10490 Mr. Azad and his Son!!!!!
/***
Md. Nazmul Hasan
Shahjalal University of Science & Technology,Sylhet.
hasan08sust@gmail.com
***/
#include<iostream>
#include<cstdio>
#include<stack>
#include<queue>
#include<map>
#include<vector>
#include<algorithm>
#include<cstring>
#include<sstream>
#include<cmath>
#include <iomanip>
using namespace std ;
typedef long long ll ;
typedef int in ;
typedef unsigned long long ull ;
const double pi = 2*acos(0) ;
#define maxi 40000
#define pf printf
#define sc scanf
#define pb push_back
#define MEM(x,y) (memset((x),(y),sizeof(x)))
#define MIN(x,y) ((x) < (y) ? (x) : (y))
#define MAX(x,y) ((x) > (y) ? (x) : (y))
#define load(array,size) for(int i=0 ; i<size ; i++) cin>>array[i] ;
#define new_line pf("\n")
#define clear_data(array) memset(array,0,sizeof(array))
#define highest_int 2147483647
int main()
{
int n,cnt;
long long int m;
int prime[] = {2,3,5,7,11,13,17,19,23,29,31};
while(sc("%d",&n) &&n)
{
cnt=0;
for(int i=0 ; i<11 ; i++)
{
if(n==prime[i])
cnt=1;
}
if(cnt==1)
{
if(n==11 || n==23 || n==29)
{
pf("Given number is prime. But, NO perfect number is available.\n");
}
else
{
m = pow(2,n-1)*(pow(2,n)-1);
pf("Perfect: %lld!\n",m);
}
}
else
{
pf("Given number is NOT prime! NO perfect number is available.\n");
}
}
return 0;
}
Md. Nazmul Hasan
Shahjalal University of Science & Technology,Sylhet.
hasan08sust@gmail.com
***/
#include<iostream>
#include<cstdio>
#include<stack>
#include<queue>
#include<map>
#include<vector>
#include<algorithm>
#include<cstring>
#include<sstream>
#include<cmath>
#include <iomanip>
using namespace std ;
typedef long long ll ;
typedef int in ;
typedef unsigned long long ull ;
const double pi = 2*acos(0) ;
#define maxi 40000
#define pf printf
#define sc scanf
#define pb push_back
#define MEM(x,y) (memset((x),(y),sizeof(x)))
#define MIN(x,y) ((x) < (y) ? (x) : (y))
#define MAX(x,y) ((x) > (y) ? (x) : (y))
#define load(array,size) for(int i=0 ; i<size ; i++) cin>>array[i] ;
#define new_line pf("\n")
#define clear_data(array) memset(array,0,sizeof(array))
#define highest_int 2147483647
int main()
{
int n,cnt;
long long int m;
int prime[] = {2,3,5,7,11,13,17,19,23,29,31};
while(sc("%d",&n) &&n)
{
cnt=0;
for(int i=0 ; i<11 ; i++)
{
if(n==prime[i])
cnt=1;
}
if(cnt==1)
{
if(n==11 || n==23 || n==29)
{
pf("Given number is prime. But, NO perfect number is available.\n");
}
else
{
m = pow(2,n-1)*(pow(2,n)-1);
pf("Perfect: %lld!\n",m);
}
}
else
{
pf("Given number is NOT prime! NO perfect number is available.\n");
}
}
return 0;
}
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