import math | |
n = int(input()) | |
i=1 | |
while i<=n: | |
x = int(input()) | |
d = (-1 + math.sqrt(1 + 8 * x)) / 2 | |
print(int(d)) | |
i = i+1 |
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This problem is quite easy. Look carefully that if we square root s and take it ceil n, then the abscissa or the ordinate will be equal to ...
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#include<iostream> #include<cstdio> #include<stack> #include<queue> #include<cstring> using namespace st...
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/*** Md. Nazmul Hasan Shahjalal University of Science & Technology,Sylhet. hasan08sust@gmail.com ***/ #include<iostream> #include...
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